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15y^2-51y+18=0
a = 15; b = -51; c = +18;
Δ = b2-4ac
Δ = -512-4·15·18
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-39}{2*15}=\frac{12}{30} =2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+39}{2*15}=\frac{90}{30} =3 $
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